NCERT Solution Class 10 math chapter 13

Surface Area and Volumes: Class 10 Mathematical NCERT Solutions Chapter 13 

Students may review many solid forms, such as cube, cone, cylinder, and cuboid, as well as the formulae for surface area and volume of these solid figures that they have previously learned, with the aid of NCERT answers for class 10 math chapter 13 Surface Area and Volumes. It is crucial to comprehend these substances and their characteristics since these ideas are part of everyday life. The surface area and volume of these solids combined will be further shown in Chapter 13 of the Class 10 Mathematics NCERT Solutions. As a result, across the course of this chapter, students will learn how to compute the combined surface area and volume of two or more solid objects. The class 10 math chapter 13 NCERT solutions will assist students in learning about a variety of subjects, including the frustum of a cone, the surface area and volume of combination solids, and solid transformation. Numerous questions in this chapter are focused on various forms and their combinations. Since the questions were chosen by professionals, each and every sum will help students learn by allowing them to explore a variety of different ideas. With the aid of this article and the tasks provided below, we will advance our study of this chapter.

Surface Area and Volumes:

• Surface Area of a cuboid of length l, breadth b, and height h = 2 (l ✕ b+ b ✕ h+ l ✕ h)

• Lateral Surface Area of cuboid = 2 ( l+ b) h

• Cube Surface Area = 6 l² where l is the length

• Lateral Surface Area of cube = 4 l² where l is the length

• Volume of cube = l³

• Cylinder's Lateral Surface Area( LSA )  = 2πrh

• Total Surface Area (TSA) of a Cylinder = 2πr (h+r)

• Volume of Cylinder = πr² h

• Lateral Surface Area of Cone = πrL

• Total surface area of cone = πr ( L+ r)

• Volume of Cone = ⅓ (πr² h)

• Surface Area of Sphere= 4 πr²

• Volume of Sphere = 4/3 (πr³)

• Volume of Frustum of cone = 1/3 πh ( r²₁ + r²₂+ r₁ + r₂)

• Total Surface Area of Frustum of cone = πL( r₁ + r₂)+π(r²₁ + r²₂)

☛ Download NCERT Solutions Class 10 Maths, Chapter 13 Full

Class 10 Chapter 13    

Surface Area and Volumes Formula:

• Surface Area of a cuboid of length l, breadth b, and height h = 2 (l ✕ b+ b ✕ h+ l ✕ h)

• Lateral Surface Area of cuboid = 2 ( l+ b) h
• Cube Surface Area = 6 l² where l is the length

• Lateral Surface Area of cube = 4 l² where l is the length

• Volume of cube = l³

• Cylinder's Lateral Surface Area( LSA )  = 2πrh

• Total Surface Area (TSA) of a Cylinder  = 2πr (h+r)

• Volume of Cylinder = πr² h

• Lateral Surface Area of Cone = πrL

• Total surface area of cone = πr ( L+ r)

• Volume of Cone = ⅓ (πr² h)

• Surface Area of Sphere= 4 πr²

• Volume of Sphere = 4/3 (πr³)

• Volume of Frustum of cone = 1/3 πh ( r²₁ + r²₂+ r₁ + r₂)

• Total Surface Area of Frustum of cone = πL( r₁ + r₂)+π(r²₁ + r²₂)